we can ase the following 0 056m. moles of substancea kgHO 23.4 x 10 From T& Reac

Question

we can ase the following 0 056m. moles of substancea kgHO 23.4 x 10 From T& Reacrasging tbs epation, you ger Moles of substance 9056 1.42 × 10. he molar mass of the etained for further computation.) The molar 01318 92.3 g/mol fgures The molecular massi 2 Aa eatra digit is retained for further Molar mass 1,42 X 10 mol 923 /mol ou round the answer to two significant figures Asower Check Mistakes often give the moality Mistales often gve unreasonable values For mass of 0.092 amu. Because the at valuad of kg H,O), you moles of substance by s H,(instead ofo the atomic mass of Camphor e stieda molecular dlensend) is L.OI amu, a value of 0.092 he 92,000 amu a value of 0.092 amu is not possible. Vy of i have reason t you haa ar substancesn should also set auteral s opymerk or biological). Typical molecular substa Cancat LE83 A0930-g sample of ascorbie acid (vitamin C amu, should also set off alarm bells (unless Answer Chen the concen that range from tens up to hundreds of amu. n C) was dissolved in ue of ascorbic acid, as determined by freezing-poi water. The concentraton wax 85 n What is the molecular mass of ascorbic acidfreezing-oind be 0.159 mula of al See Problems 12.73 ap 1212 Calalating he Molecalar Mass from Freezing Point Depression Erample Cainphor is a wbite solid that melts at 179.5 C. It has been used to determine the cosant (Clm), shich allows ordinary thermometers to be used. The orgac 12.7 Osmosis a3 ar mases of oganic compounds because of its unusually large fr mine the nole sce is dssolved in meciteod camphor, and then the melting point of the soluticn nned D A 107.mg sample of a compound was dissolved in 78. 1 mgofamphl Certain membranes allowe srmal bat not larger, solvated solute molecular mass Such a mem an ainnal bladder, a vegetabie depicts the operation of a se ·" mipm-nched at 176rc wha is the molecular mass of the compound, ditt mpical formaia of the compoued is CH, what is the molecular formula? Th hproblem is to determine the molality of the solution.Given the iniornsn the solution. Grve thn provides s pech or of the same solvens are sep molecules migate thog the solvent migration is fa tion to the sohutison e hw 47

Explanation / Answer

Kb of CS2 = 2.44 K Kg mol-1

dT = elevation in boiling point = 0.159 oC

dT = Kb x molality

0.159 = 2.44 x molality

molality = 0.065 m

molality = moles of solute / mass of solvent in kg

0.065 = moles / (25 x 10^-3)

moles of solute = 1.63 x 10^-3

mass / molar mass = 1.63 x 10^-3

0.205 / molar mass =1.63 x 10^-3

molar mass = 125.8 g /mol

molecular mass of phosporous solution = 125.8 g/mol

formula of molecular phosphorous = P4

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