OVLv2]Online teachi.- Co -My H0WLv2| Online tea...X 15 Pr . Search ..I ta Share

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OVLv2]Online teachi.- Co -My H0WLv2| Online tea...X 15 Pr . Search ..I ta Share | More » mnen og Search Amazon and the Web Music . Skins- Downloads- > Support- . ECloud piayer pare Drive Search Use the Keserences to access important values ut aeeded tor this question The equilibrium constant, K, for the following reaction is 7.00 10 at 673 K If an equilibrium mixture of the three compounds in a 7.30 L container at 673 K contains 2.31 mol of NH,I(s) and 0.420 mol of NH, the sumber of moles of Hl present is moles. Retry Entire Group No more group attempts remain Nest

Explanation / Answer

NH4I(s) <------> NH3(g) + HI(g)

Kc = [NH3][HI] / [NH4l] = 7.00 x 10^-5

Now calculate the concentration of NH4I and NH3 as follows:

[NH4l] = 2.31 mol / 7.30 L = 0.32 M

[NH3] = 0.420 mol / 7.30 L = 0.058 M

Then

Kc = [NH3][HI] / [NH4l]

7.00 x 10^-5=0.058 M [HI] / 0.32 M

[HI] = 3.86*10^-4 M

Now number of moles can be calculated as follows:

[Hl] = mol / 7.30 L = 3.86*10^-4 mol / L

mol of HI = 2.8*10^-3 moles

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