OStat 301 Module 3 Homewc Stat 301 Module 3 Hom X + v Ohttps:/www.webasign.net d

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OStat 301 Module 3 Homewc Stat 301 Module 3 Hom X + v Ohttps:/www.webasign.net dep- 19369877 A professor has noticed that, even though attendance is not a component of the final grade for the class, students that attend regularly generally get better grades. In fact, this class profile, suppose we are randomly selecting a single student from this class, and answer the questions below 45% of those who come t class on a regular basis receive A's Only 8% who do not attend regularly get A's Overall, 60% of students attend regula y Based on are 1000 students in the class and use the values given in the problem to construct the appropriate contingency table. Round cel frequencies to the nearest integer Hint #2: No joke, you really need to use hint #1. Hint #3: The first step to using hint #1 is to calculate the totals for those who attend regularly and do not attend regularly A) P(receives A's I attends regularly)045 Use 2-decimal precision in your answer B) P(receives A's l does not attend regularly)-1008 Use 2-decimal precision in your answer C) P(receives A's)0.302 Use 3-decimal precision in your answer D) P(attends regularly | receives A's) 0.894 Use 3-decimal precision in your answer E) P(does not attend regularly I does not receive A's)0.368x Use 3-decimal precision in your answer Submit Answer Save Progress Practice Another Version d9 O Type here to search

Explanation / Answer

A) P(got A's | attends regularly) = 270/600= 0.45

B)    P(got A's | doesnot attends regularly) = 32/400 = 0.08

C) P(receives A's) = 302/1000 = 0.302

D) P[Attends regularly | receives A's] = 270/302 = 0.894

E) P[Doesnot attend regularly | doesnot receive A ] = 368/698 = 0.527

If you have doubts, let me know below. Thanks

Attends regulary Not regular Total Got A 270 32 302 Did not get A 330 368 698 Total 600 400 1000

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