Molar mass A. )Use the molar volume of a gas at STP, find the number of moles of

Question

Molar mass
A. )Use the molar volume of a gas at STP, find the number of moles of O2 in 112 L O2 gas.
N1= ? Mol
B.)Use the molar volume of a gas at STP, find the number of moles of CO2 in 7.20 L CO2 gas.
N2= ? Mol
C.)Use the molar volume of a gas at STP, find the volume (L) of 9.00 g O2
V1= ?L
D.) use the molar volume of a gas at STP, find the volume (ML) occupied by 42.0 g neon.
V2= ? mL Molar mass
A. )Use the molar volume of a gas at STP, find the number of moles of O2 in 112 L O2 gas.
N1= ? Mol
B.)Use the molar volume of a gas at STP, find the number of moles of CO2 in 7.20 L CO2 gas.
N2= ? Mol
C.)Use the molar volume of a gas at STP, find the volume (L) of 9.00 g O2
V1= ?L
D.) use the molar volume of a gas at STP, find the volume (ML) occupied by 42.0 g neon.
V2= ? mL
A. )Use the molar volume of a gas at STP, find the number of moles of O2 in 112 L O2 gas.
N1= ? Mol
B.)Use the molar volume of a gas at STP, find the number of moles of CO2 in 7.20 L CO2 gas.
N2= ? Mol
C.)Use the molar volume of a gas at STP, find the volume (L) of 9.00 g O2
V1= ?L
D.) use the molar volume of a gas at STP, find the volume (ML) occupied by 42.0 g neon.
V2= ? mL

Explanation / Answer

a)

1 mol in 22.4 L

n mol in 112 L ?

n = 112/22.4 = 5 mol

B)

1 mol = 22.4 L

7.20 L --> 7.20/22.4 = 0.321 mol

C)

1 mol = 22.4L

mol O2 = mass/MW = 9/32 = 0.281 mol

then

0.281/1*22.4 = 6.294 L

d)

m = 42 g Neon

MW = 20.1

mol = 42/20.1 = 2.08955 mol

1 mol = 22.4 L

2.095 mol --> V?

2.095*22.4 = 46.9 liter

or 46900 ml

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