Molar heat of neutralization will always be an exothermic (i.e. negative) value?

Question

Molar heat of neutralization will always be an exothermic (i.e. negative) value?

Question 1 options:

True

False

Question 2

If you determine the molar heat of neutralization for an acid is 49.1 kJ/mol and the accepted value is found to be 55.2 kJ/mol, the what is the percent error in your answer?

Question 2 options:

6.1%

10%

11%

15%

Question 3

What is the molar heat of neutralization (Enthalpy of Reaction) in kJ/mol if 5 moles of HA neutralized 5 moles of BOH and released 8137 J of heat?

Your Answer:Question 3 options:

Question 4

Calculate the molar heat of neutralization in kJ/mol of the reaction between HA and BOH given the following information:
The temperature change equals 9C,
50 mL of 1 M concentration of Acid
50 mL of 1 M concentration of Base
Heat capacity of the calorimeter is 6.5 J/C.
Remember that the specific heat of water is 4.18 J/gC

Your Answer:Question 4 options:

Question 5 Save

How much heat is gained (in Joules) by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 11 C?

True

False

Explanation / Answer

1)
Yes it is always true
Answer: True

2)
difference = 55.2 - 49.1 = 6.1 KJ

% error = difference * 100 / accepted value
= 6.1*100/55.2
= 11 %

Answer: 11 %

3)
for 5 moles of neutralisation, heat released = 8137 KJ
for 1 mol, it is 8137/5 = 1627.4 J/mol = 1.63 KJ/mol
Answer: 1.63 KJ/mol

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