A man accidentally mixed 6% by mass sodium hypochlorite and 20% by mass sodium t

Question

A man accidentally mixed 6% by mass sodium hypochlorite and 20% by mass sodium thiosulfate. He claims to have suffered second degree burns after having the solution on his skin for approximately 10 seconds. By mixing several 25mL combinations of the solutions in a lab (with concentration 0.5M for both, which is different than in the dumpster), I have found that the highest temperature change comes from 18.75 mL Sodium Thiosulfate ad 6.25 mL of Sodium Hypochlorite, resulting in a temperature change of 23 degrees Celsius.

This gives me a chemical equation of 3(sodium thiosulfate) + 1(sodium hypochlorite) ==> heat

What was likely the reaction temperature inside the dumpster?

Was this enough to cause third degree burns?

Please explain thoroughly, I'm having trouble grasping this concept. I believe I've given all of the information I have. Though, if you need something else, ask and I will provide it if possible. Thank you.

Explanation / Answer

6% NaClO=0.06*25=1.5g   20%Na2S2O3=0.2*25=5g
g NaClO=0.5*74.44*0.025=0.9305g
g Na2S2O3=0.5*158.11*0.025=1.976375g

given concentration apparently takes three times by weight of sodium thiosulfate, but only less than that concentration sufficient to produce severe burning is achieved in terms of the sample with the individual burn if spared which was the same amount of volume that was created with the calculations, the first sample had a higher concentration than expected, so that was enough to produce such a burn.

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