Nitroglycerin decomposes violently according to the balanced chemical equation b

Question

Nitroglycerin decomposes violently according to the balanced chemical equation below. 4 C3Hs(NO2)3(1)rightarrow 6 N2(g) + O2(g) + 12 CO2(g) + 10 H2O(g) Which of the following statements concerning this reaction is/are CORRECT? Two moles of nitroglycerine will produce three moles of nitrogen and five moles o f water. Four molecules of nitroglycerine will produce one molecule of oxygen and twelve molecules of carbon dioxide Six grams o f nitroglycerine will produce nine grams of nitrogen and fifteen grams of water.

Explanation / Answer

Solution :-

Mole ratio of the nitroglycerin to nitrogen is 4 :6 and with water is 4 : 10

Therefore when 2 mole nitroglycerin is used then it will product

2 mol C3H5(NO3)3 * 6 mol N2 /4 mol C3H5(NO3)3 = 3 mol N2      ( correct)

2 mol C3H5(NO3)3 *10 mol H2O / 4 mol C3H5(NO3)3 = 5 mol H2O   correct

Statement 1 is correct

Now lets find statement 2

4 molecule C3H5(NO3)3 = 1 molecule oxygen

4 molecules C3H5(NO3)3 = 12 molecules of CO2

Correct

Statement 2 is also correct

Now statement 3

1 mol C3H5(NO3)3 = 227.08 g

Therefore if we use 6 g C3H5(NO3)3 then its moles are

6 g C3H5(NO3)3 * 1 mol / 227.08 g = 0.0264 mol

Now lets calculate moles of N2

0.0264 mol C3H5(NO3)3 * 6 mol N2 / 4 mol C3H5(NO3)3 = 0.0396 mol N2

Now lets convert moles of N2 to its mass

Mass = moles * molar mass

             = 0.0396 mol N2 * 28.014 g per mol

            = 1.11 g

It can only produce 1.11 g N2

Therefore nine gram nitrogen cannot be produced

This means stamen   is incorrect

So statement   1 and statement 2 are correct

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