kinetics competing parallel reactions. a)At 1100 K, acetic acid decomposes via 2

Question

kinetics competing parallel reactions.

a)At 1100 K, acetic acid decomposes via 2 competing, first order reactions: CH3COOH -> CH4 + CO2, k1 = 5.2 s-1 CH3COOH -> CH2=C=O + H2O, k2 = ? s-1 The half life of acetic acid at this temperature is 0.12 s. What is the value of the rate constant, k2?

competing parallel reactions.

The correct answer is: 0.576(why? ) what's the formula? I keep getting wrong answers

b)

At 1100 K, acetic acid decomposes via 2 competing, first order reactions:

CH3COOH -> CH4 + CO2,   k1 = 1.8 s-1

CH3COOH -> CH2=C=O + H2O,    k2 = ? s-1

At 1100K, the yield of ketene (CH2=C=O) is 76.5%. Estimate the rate constant, k2, for the second reaction.

The correct answer is: 5.86( please explan which formula to use)

Explanation / Answer

answer no.1

a)At 1100 K, acetic acid decomposes via 2 competing, first order reactions: CH3COOH -> CH4 + CO2, k1 = 5.2 s-1 CH3COOH -> CH2=C=O + H2O, k2 = ? s-1 The half life of acetic acid at this temperature is 0.12 s. What is the value of the rate constant, k2?

competing parallel reactions.

solution: rate constant = 0.693/T1/2

=0.693/ 0.12

=0.576

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