kinemetic problem qn 67 ASAP with explanation please Chapter 3 Motion Along a St

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kinemetic problem qn 67 ASAP
with explanation please

Chapter 3 Motion Along a Straight Line How long a time does he have to g shot was released at a height of 2. 3.5 Free Fall 66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown straight up with an initial velocity of 15.0 m/s. Take the point of release to be yo 0 74. You throw a ball straight upv 15.0 m/s. It passes a tree brancho of 7.0 m. How much additional tin passes the tree branch on the way 67. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, (d) 2.00 s, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge in New York City.speed when it leaves the ground. 75. A kangaroo can jump overa Considering just its vertical mo The roadway of this bridge is 70.0 m above the water.i he air2 A basketball referee tosses the ball straight up for the 76. Standing at the base of one 68. starting tip-off. At what velocity must a basketball player leave the ground to rise 1.25 m above the floor in an in victoria attemnt to get the ball? in Victoria, Australia, a hiker he a height of 105.0 m. He can't s then does, 1.50 s later. (a) Hov

Explanation / Answer

here,

67)

initial speed , u = 14 m/s

height , h0 = 70 m

a)

at t = 0.5 s

the final displacement , s = u * t + 0.5 * g * t^2

s = 14 * 0.5 + 0.5 * 9.81 * 0.5^2 m

s = 8.23 m

the final velocity , v = u + g * t

v = 14 + 9.81 * 0.5 m/s

v = 18.9 m/s

b)

at t = 1 s

the final displacement , s = u * t + 0.5 * g * t^2

s = 14 * 1 + 0.5 * 9.81 * 1^2 m

s = 18.91 m

the final velocity , v = u + g * t

v = 14 + 9.81 * 1 m/s

v = 23.81 m/s

c)

at t = 1.5 s

the final displacement , s = u * t + 0.5 * g * t^2

s = 14 * 1.5 + 0.5 * 9.81 * 1.5^2 m

s = 32 m

the final velocity , v = u + g * t

v = 14 + 9.81 * 1.5 m/s

v = 28.7 m/s

d)

at t = 2 s

the final displacement , s = u * t + 0.5 * g * t^2

s = 14 * 2 + 0.5 * 9.81 * 2^2 m

s = 47.6 m

the final velocity , v = u + g * t

v = 14 + 9.81 * 2 m/s

v = 33.6 m/s

e)

at t = 2.5 s

the final displacement , s = u * t + 0.5 * g * t^2

s = 14 * 2.5 + 0.5 * 9.81 * 2.5^2 m

s = 65.7 m

the final velocity , v = u + g * t

v = 14 + 9.81 * 2.5 m/s

v = 38.5 m/s

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