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2 NaHCO3 (s) + HC2H3O2 (l) = CO2(g) + 2NaC2H3O2 (s) + H2O (l) 1) I used 1 gram o

ID: 896634 • Letter: 2

Question

2 NaHCO3 (s) + HC2H3O2 (l) = CO2(g) + 2NaC2H3O2 (s) + H2O (l)
1) I used 1 gram of each reactant. calculate the volume of CO2 gas that resulted from each reactant at room temperature which was 65 F and oven temperature which was 325 F. You are at sea level. You will have two calculations. Decide which reactant is the limiting.
2) which volume is the volume of my cake after baking?
3) how could I increase the volume of gas produced to make the cake rise more?
4) what would my volume of the cake be in Colorado Springs? 2 NaHCO3 (s) + HC2H3O2 (l) = CO2(g) + 2NaC2H3O2 (s) + H2O (l)
1) I used 1 gram of each reactant. calculate the volume of CO2 gas that resulted from each reactant at room temperature which was 65 F and oven temperature which was 325 F. You are at sea level. You will have two calculations. Decide which reactant is the limiting.
2) which volume is the volume of my cake after baking?
3) how could I increase the volume of gas produced to make the cake rise more?
4) what would my volume of the cake be in Colorado Springs? 2 NaHCO3 (s) + HC2H3O2 (l) = CO2(g) + 2NaC2H3O2 (s) + H2O (l)
1) I used 1 gram of each reactant. calculate the volume of CO2 gas that resulted from each reactant at room temperature which was 65 F and oven temperature which was 325 F. You are at sea level. You will have two calculations. Decide which reactant is the limiting.
2) which volume is the volume of my cake after baking?
3) how could I increase the volume of gas produced to make the cake rise more?
4) what would my volume of the cake be in Colorado Springs?

Explanation / Answer

The correct balanced equation is

NaHCO3 + CH3COOH - > CH3COONa + H2O + CO2

65F=18.333 C = 291.333 K

325 F=162.778 C=435.778 K

moles of NaHCO3 = 1/84

moles of HC2H3O2= 1/60

now since the number of moles of the bicarbonate is smaller, NaHCO3 is the limitng reagent.

now using the ideal gas equation,

PV=nRT

or 1*V=(1/84)*(1/12)*291.33

or V=0.289 L

at 325F,

1*V=(1/84)*(1/12)*435.778

or V=0.432 L

2)second volume is the volume of the cake after baking since the temperature of the cake is 325F

3)we can increase the volume by either increasing the quantity of the bicarbonate or by increasing the temperature of the oven.

4)use the same gaas equation to get the result since the value of temperature at colorado spring varies at each point of the day

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