2 It has no magnitude so the direction isirrelevant. Due east (along the positiv

Question

2 It has no magnitude so the direction isirrelevant.
Due east (along the positivex-axis)   
Due north (along the positivey-axis)
Due west (along the negativex-axis)
Due south (along the negativey-axis)
A northeasterly direction (firstquadrant)
A northwesterly direction (secondquadrant)
A southwesterly direction (thirdquadrant)
A southeasterly direction (fourthquadrant) 2 It has no magnitude so the direction isirrelevant.
Due east (along the positivex-axis)   
Due north (along the positivey-axis)
Due west (along the negativex-axis)
Due south (along the negativey-axis)
A northeasterly direction (firstquadrant)
A northwesterly direction (secondquadrant)
A southwesterly direction (thirdquadrant)
A southeasterly direction (fourthquadrant) 2

Explanation / Answer

Vector A = 15 sin 42 i + 15 cos 42 j                = 10.03 i + 11.147 j Vector B = 10 cos 10 ( -i ) + 10 sin 10 ( -j )               = - 9.848 i - 1.736 j where i , j are the unit vectors in east , northdirections respectively. So, A + B = ( 10.03 -9.848 ) i + ( 11.147 - 1.736 )j                 = 0.1888 i + 9.41 j magnitude of A+B is = [ 0.1888 ^ 2 + 9.41 ^ 2 ]                                = 9.412 m ( 2) . Both the components of the vector A+ B arepositive.So, the vector in northeasterly direction (firstquadrant) ( 3 ) . Let the vector A+ B makes an angle with x - axis then tan = 9.41 / 0.1888                  = 88.85 degrees ( 3 ) . Let the vector A+ B makes an angle with x - axis then tan = 9.41 / 0.1888                  = 88.85 degrees

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