2 It has no magnitude so the direction isirrelevant. Due east (along the positiv

Question

2 It has no magnitude so the direction isirrelevant. Due east (along the positivex-axis)     Due north(along the positive y-axis) Due west (alongthe negative x-axis) Due south (along the negativey-axis) A northeasterly direction (firstquadrant) A northwesterly direction (secondquadrant) A southwesterly direction (thirdquadrant) A southeasterly direction (fourthquadrant) 2 It has no magnitude so the direction isirrelevant. Due east (along the positivex-axis)     Due north(along the positive y-axis) Due west (alongthe negative x-axis) Due south (along the negativey-axis) A northeasterly direction (firstquadrant) A northwesterly direction (secondquadrant) A southwesterly direction (thirdquadrant) A southeasterly direction (fourthquadrant) 2

Explanation / Answer

Vector A = 25 sin 75 i + 25 cos 75 j

               = 24.14 i+ 6.47 j

Vector B = 27 cos 65 (-i) + 27 sin 65(-j)

              = -11.41i-24.47j

Resultant vector C = A + B

                              = -12.73i -18 j

Magnitude of resulatnt vector = [ (-12.73^2 +(-24.47)^2]

                                             = 27.58

(b). A southwesterlydirection (third quadrant)

(c).let it makes an angle with negative x- axis incounterclock direction then tan = 18/12.73

         = 54.73degrees

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