1.A normal breath of air is about 1.00 L. If the air is drawn in at -13.0 C and
ID: 893459 • Letter: 1
Question
1.A normal breath of air is about 1.00 L. If the air is drawn in at -13.0 C and is warmed to 31.0 C, what will be the new volume of the air? Assume that the pressure and amount of the gas remain constant.
2.Which of the following would you expect to dissolve in water?
a,NaCl b,C8H18 C,C5H12 D,Li2CO3
3.A sample of gas in a balloon has an initial temperature of 39 C and a volume of 1980 L . If the temperature changes to 71 C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?
4.What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1= 39 C , V1= 1980 L ) to a volume of 3960 L ? Assume no change in pressure or the amount of gas in the balloon.
5.If the volume of the balloon increases to 8.85 L , what will the final pressure within the balloon be if the temperature does not change?
Explanation / Answer
Answer:
1). T1 = -13 +273 = 260K
T2 = 31+273 = 304K
V1 = 1L
V1/T1 =V2/T2
V2 = (V1*T2)/T1
= (1*304)/260
= 1.169 L
2) a). NaCl
3).
T1 = 39 +273 = 312 K
V1 = 1980 L
T2 = 71 +273 = 344 K
V1/T1 =V2/T2
V2 = (V1*T2)/T1
= (1980*344)/312
= 2183 L
4). T1 = 39+273 = 312 K
V1 = 1980 L
V2 = 3960 L
V1/T1 = V2/T2
T2 = (V2*T1)/V1
= (3960*312)/1980
= 624 K
5) Needs complete information for solving
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