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Rit C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-1960325 Sapling Lea

ID: 890184 • Letter: R

Question

Rit C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-1960325 Sapling Learning Northwest Oklahoma State University CHEM 11 Activities and Due Dates 5 WICKHAM HW 3 My Assignment O 9/30/2015. 11:55 PM A o/100 Gradebook Attempts Print Tab Calculator Questi of 8 What is the maximum mass of S8 that can be produced by combining 86.0 g of each reactant? 8SO 6H,O Number g S Previous Give Up & View Solution Check Answer Next Exit Topic 2bb (1)pptx Search the web and Window Resources Assignment Information Available From: 9/6/2015 06:00 PM 9/30/2015 11:55 PM Due Date: Points Possible: 100 Grade Category: Graded Description: Policies: Homework n check your answers. n view solutions when you complete or give up on any question n keep trying to answer each question until you get it right or give up You lose 5% of the points available to each answer in your question for each incorrect attempt atthat o Help With This Topic Web Help & Videos O Technical Support and Bug Reports Logo 28 PM

Explanation / Answer


Sulfur dioxide Molar mass = 64.066 g/mol

no of mole of SO2 = 86/64.066 = 1.342 mole

MOLARMASS OF H2S = 34.0809 g/mol

No of moles of H2S = 86/34.0809 = 2.52 mole

from equation 8 mole so2 = 16 mole h2s = 3 mole s8


limiting reagent is H2S

so that,

No of moles of S8 produced = 2.52*3/16 = 0.4725 mole

molarmass of S8 = 256.5200 g/mol

mass of S8 = 0.4725*256.5200 = 121.2057 grams

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