1) 1.0 mol of an ideal gas is compressed isothermally from 2.0 atm and 2.0L to 4
ID: 887686 • Letter: 1
Question
1) 1.0 mol of an ideal gas is compressed isothermally from 2.0 atm and 2.0L to 4.0atm and 1.0 L? Calculate the values of dU and dH if the process is done a) reversibly and b) irreversibly?2) calculate the value of dH when the temperature of 1 mol of a mono atomic gas is increased from 25 C to 300 C ? 1) 1.0 mol of an ideal gas is compressed isothermally from 2.0 atm and 2.0L to 4.0atm and 1.0 L? Calculate the values of dU and dH if the process is done a) reversibly and b) irreversibly?
2) calculate the value of dH when the temperature of 1 mol of a mono atomic gas is increased from 25 C to 300 C ?
2) calculate the value of dH when the temperature of 1 mol of a mono atomic gas is increased from 25 C to 300 C ?
Explanation / Answer
1. In an isothermal reversible process dU and dU is always zero. dU and dH are functions of temperature.
dU= 3/2 (nR dT), and dH= Cv n dT
as dT is zero, dU and dH are zero.
Both dU and dH are state functions. Thus for an isothermal irreversible process the values of dU and dH will be zero too.
2. For amonoatomic gas, Cp= 5/2 * R
Cp = ( 5 / 2 ) ( 8.314 J/ mol. K) = 20.785 J / mol. K
dH = ( n ) ( Cp ) ( T2 - T1)
dH = ( 1mol ) ( 20.785 J / mol.K ) ( 573 K - 298 K )
dH = 5716 J
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