Laboratory gas bottle used in laboratory studies of hypoxia contains gas of the
ID: 886374 • Letter: L
Question
Laboratory gas bottle used in laboratory studies of hypoxia contains gas of the followingcomposition, expressed as volume percent: O2, 18.0%; N2, 80.0%; CO2, 2.0%.
(a) calculate the partial pressure of each Think asked component. Pursue atmospheric pressureof 760 mmHg.
(b) Assume that the gas is bottled and 2.0 L rigid vessel. Temperature in the lab is 23°C. Thegauge on the gas bottle reads 1500 PSI. How many moles of gas are in the bottle? How manymoles of each component are in the gas?
(c) In the pulmonary function lab, a patient exhales a quantity of gas. The technician reports thatthe volume of gas, measured at 752 mmHg and 22°C, is 1.5 L. What volume with this gasoccupy at STP?
Explanation / Answer
a)
since 22.4 L of any gas is 1 mol.
Mole fraction is another way of volume fraction.
Mole fraction of O2 = V (O2) / Vall = 18/100 = 0.18
Mole fraction of N2 = 80/100 = 0.8
Mole fraction of CO2 = 2/100 = 0.02
b)
1 psi = 0.068 atm
so,
pressure = 1500 psi = 1500*0.068 atm = 102 atm
use:
P*V = n*R*T
102 * 2 = n*(0.0821)*(273+23)
n = 8.4 mol
So, total number of moles is 8.4 mol.
mol of O2 = mole fraction of O2 * total mol = 0.18*8.4 = 1.512 mol
mol of N2 = 0.8*8.4 = 6.72 mol
mol of CO2 = 0.02*8.4 = 0.168 mol
c)
standard temp = 273 K
standard pressure = 760 mm Hg
use:
P1*V1/T1 = P2*V2/T2
752 *1.5 / (273+22) = 760*V2/273
V2 = 1.37 L
Answer: 1.37 L
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