Look at the chart that shows the stability of an isotope as a function of the nu

Question

Look at the chart that shows the stability of an isotope as a function of the number of neutrons and protons What would be the correct predicted behavior for a hypothetical isotope of stable radioactive a. It will change to-B Choose one 12 answer O b. It will decay to 1:B by emission. C. It will change to Li O d. It will decay to ini by + emission Which statem ent about the decay of C is not correct? 14 14 stable radioactive Choose one a. Carbon-14 changes to nitrogen-14 by beta emission. answer O b. A -particle is emitted in this reaction O c. The nitrogen isotope has 14 nucleons. O d. Inside the nucleus of C, a proton is changed into a neutron

Explanation / Answer

N = A - Z

Where N: numbers of neutrons,

A: atomic mass

Z: atomic number.

In this chart, we can actually calculate the numbers of neutrons of the 10 4 Be

N = 10 - 4 = 6.

Now, to determinate the hypothetical behavior of this, we need to see the chart:

If you see carefully, you'll see that for the part with 6 neutrons (Y axis) and Z = 4 (X axis), the Be is radioactive, this means that it's having a Beta emission, and it will decay to the next stable isotope. The next one it's atomic number 5. With this you can actually say that the correct answer in this part would be Option B it will decay to 10 5 B by Beta emission.

b) Following the previous part, the numbers of neutrons of Carbon is: N = 14 - 6 = 8 neutrons. Then let's look at the chart; if you see carefully, it actually decays like the previous part, because it's radioactive, so it will decay to the next stable isotope (Atomic number 7, Nitrogen), so option A is correct, and by the look of the reaction, a Beta- particle is emmited in the reaction. That's the one that let the passing of 6 to 7. Option C is also correct because Nitrogen has the 14 nucleons (Numbers of neutrons has not changed). So the only option that it's incorrect would be option D.

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