Look at the circuit below (Note how the current runs). a) What is the current in

Question

Look at the circuit below (Note how the current runs).

a) What is the current in the circuit?

b) What is the terminal voltage from a to b?

c) What is the terminal voltage from c to d?

d. What is the voltage from a to d?

e. What is the electric potential (voltage) at point a?

f. Now reverse the 10 V Battery and asnwer a-e again.

I just worked through this on my own, but I am very shaky on my logic, and I would not be willing to try to help someone else do this, for I am very unsure if I did it correctly, so any help and justifications on this is greatly appreciated. I really want to understand this material. Thanks.

Explanation / Answer

(a) We can use Kirchoff's voltage law to find out the current in the circuit

according to this sum of voltage gain and voltage drop is equal to zero

We can take direction of current counterclockwise

if we start from a then b ,d,c,a in this loop sum of voltage can be written as

I*R1 - 20 +I*R2 + 10 + I*R3 + I*R4 = 0

I(1) - 20 + I(3) + 10 +I*(1) + I*(5) = 0

10 *I - 10 =0

10 I = 10

I = 1 amp

(b) Terminal voltage across ab is

Vab = 20 - I*R1

Vab = 20 - (1)(1)

Vab = 19 volt

(c) Vcd = 10 - I*R3

Vcd = 10 - (1)(1)

Vcd = 9 volt

(d) Vad = 20 - 1*1 - 1*3

Vad = 16 volt

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