A voltaic cell is made by immersing a Zn electrode in 1 M Zn(NO3)2 solution in a

Question

A voltaic cell is made by immersing a Zn electrode in 1 M Zn(NO3)2 solution in a beaker as one half cell and a Pt electrode in 1 M FeCl2/FeCl3 solution in a beaker as the other half cell. the electrodes are connected with a wire and the two beakers are connected by a salt bridge.

Half reactions given

Fe^3+ (aq) + e^- ---> Fe^2+ E= .77

Zn^2+ + 2e^- ---> Zn (s) E= -.76

A) Which is the anode and cathode in this cell?

B) Write the anodic and cathodic half reactions and the cell reaction.

C) Write the cell notation

D) Caculate the standard cell potential.

Explanation / Answer

A) The electrode which has high reduction potential value is cathode.

=> Pt electrode in 1 M FeCl2/FeCl3 solution is cathode.

B)

Anodic half cell : Zn(s) ------------> Zn^2+ (aq) + 2e-

Cathodic half cell : 2Fe^3+(aq) + 2e-   ----------------> 2Fe^2+(aq)

cell reaction : Zn(s) + 2Fe^3+(aq) -------------> Zn^2+(aq) + 2Fe^2+(aq)

C)

Zn(s)/Zn^2+(1M) // Fe^3+/Fe^2+(1M) , Pt

D)

E0cell = E0cathode - E0anode

E0cell = 0.77 - (-0.76)

E0cell = 1.53 V

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