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1) 2) Which of the following carbocations will be the most stable and most likel

ID: 856112 • Letter: 1

Question

1)

2) Which of the following carbocations will be the most stable and most likely carbocation formed during the solvolysis of 1-chloro-2-methylcyclohexane in CH3OH?

3)Which of the following compounds shown below will be the most likely product formed as the result of an alkyl shift during the solvolysis of 1-iodo-2,2-dimethylpentane in CH3OH?

4) Which of the following carbocations will be the most stable and most likely carbocation formed during the solvolysis of 2-bromo-3,3-dimethylpentane in CH3OH?

5)What is the order of decreasing stability of the carbocations shown below?

6)Which product(s) will be formed in the SN2 reaction shown below?

7) Which compound shown below is the major product formed when the solvolysis of 2-iodo-3-methylpentane in CH3OH proceeds with a hydride shift?

2) Which of the following carbocations will be the most stable and most likely carbocation formed during the solvolysis of 1-chloro-2-methylcyclohexane in CH3OH? 3)Which of the following compounds shown below will be the most likely product formed as the result of an alkyl shift during the solvolysis of 1-iodo-2,2-dimethylpentane in CH3OH? 4) Which of the following carbocations will be the most stable and most likely carbocation formed during the solvolysis of 2-bromo-3,3-dimethylpentane in CH3OH? 5)What is the order of decreasing stability of the carbocations shown below? 6)Which product(s) will be formed in the SN2 reaction shown below? 7) Which compound shown below is the major product formed when the solvolysis of 2-iodo-3-methylpentane in CH3OH proceeds with a hydride shift?

Explanation / Answer

1) B Aryl halide do not undergo nucleophilic substitution reaction due to it has lone pair which donate benzene ring to produce double bond that is why aryl halide not easily substitute by incoming nucleophile.

2) B First halide leave to form secondary carbocation which is less stable than tertiary that is 1,2 hydride shift takes place.

3) A Tertiary carbocation is more stable.

4) C Here given two tertiary carbocation hence answer either c or d but Tertiary carbocation stabilized by alpha hydrogens therefore option c has 8 alpha hydrogens but option d has only 5 alpha hydrogens. that is why C is more stable

5) C>A>B tertiary carbotion more stable than secondary carbocation whereas secondary carbocaation is more stable than primary carbocation.

6) C Inversion takes place.

7) C