1) 2) 3) 4) Find parametric equations for the path of a projectile launched from

Question

1) 2) 3) 4) Find parametric equations for the path of a projectile launched from height h equals twelve ft with initial speed v equals fifteen ft/s at angle theta equals nine degrees from the horizontal System of two equations. First x equals fourteen and ninety-eight hundredths times t. Second: y equals minus sixteen times t squared plus zero and seventy five hundredths times t plus twelve System of two equations. First x equals fifteen t. Second: y equals minus sixteen t squared plus twelve System of two equations, First: x equals minus sixteen t squared plus fourteen and ninety-eight hundredths times t plus twelve. Second: y equals minus sixteen t squared plus fourteen and seventy five hundredths times t plus twelve Systems of two equations: First; x equals minus sixteen t squared plus fifteen t. second : y equals minus sixteen t squared plus fifteen t plus twelve

Explanation / Answer

x= 15*cos 9 t=14.98t

y=15 sin9t-0.5gt^2+12=-16t^2+0.75t+12

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