1) 2) 3) 4) Find parametric equations for the path of a projectile launched from

Question

1) 2) 3) 4) Find parametric equations for the path of a projectile launched from height h equals twelve ft with initial speed v equals fifteen ft/s at angle theta equals nine degrees from the horizontal System of two equations. First x equals fourteen and ninety-eight hundredths times t. Second: y equals minus sixteen times t squared plus zero and seventy five hundredths times t plus twelve System of two equations. First x equals fifteen t. Second: y equals minus sixteen t squared plus twelve System of two equations, First: x equals minus sixteen t squared plus fourteen and ninety-eight hundredths times t plus twelve. Second: y equals minus sixteen t squared plus fourteen and seventy five hundredths times t plus twelve Systems of two equations: First; x equals minus sixteen t squared plus fifteen t. second : y equals minus sixteen t squared plus fifteen t plus twelve

Explanation / Answer

the horizontal componet i.e 'x' is independent of force

So, x=u*cos( theta)*t

x=15*cos(9 degrees)*t

x=14.98t

So, option 1 is correct

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