1) 12-g bullet with an initial speed of 297 m/s is shot directly at a 1-kg woode
ID: 1367461 • Letter: 1
Question
1) 12-g bullet with an initial speed of 297 m/s is shot directly at a 1-kg wooden block, which rests on a frictionless surface. What is the speed of the block, after the bullet is embedded in the block?
(Although this is not justified, calculate your answer to 4 significant figures. This will uncover any conceptual errors you might make.)
2) 12-g bullet with an initial speed of 292 m/s is shot directly at a 1.1-kg wooden block, which rests on a frictionless surface. The bullet passes through the block and emerges with a speed of 274 m/s. What is the speed of the block, after the bullet has passed through the block?
3) 12-g bullet with an initial speed of 292 m/s is shot directly at a 1.1-kg wooden block, which rests on a frictionless surface. The bullet passes through the block and emerges with a speed of 274 m/s. What is the speed of the block, after the bullet has passed through the block?
2) 12-g bullet with an initial speed of 292 m/s is shot directly at a 1.1-kg wooden block, which rests on a frictionless surface. The bullet passes through the block and emerges with a speed of 274 m/s. What is the speed of the block, after the bullet has passed through the block?
3) 12-g bullet with an initial speed of 292 m/s is shot directly at a 1.1-kg wooden block, which rests on a frictionless surface. The bullet passes through the block and emerges with a speed of 274 m/s. What is the speed of the block, after the bullet has passed through the block?
Explanation / Answer
from momentum conservation total momentum before collision = total momentum after collision
iniital momemtum = final moentum
m1*u1 + m2*u2 = m1*v1 + m2*v2
(1)
after the bullet & block are has same speed v1 = v2 = V
u1 = 297 m/s u2 = 0
m1 = 0.012 kg
m2 = 1 kg
(0.012*297)+0 = (0.012+1)*V
v = 3.52 m/s
(2)
m1 = 0.012 kg m2 - 1.1 kg
u1 = 292 m/s u2 = 0
v1 = 274 m/s v2 = ?
(0.012*292)+(0) = (0.012*274)+(1.1*v2)
v2 = 0.196 m/s
+++++++++++++++
(3)
m1 = 0.012 kg m2 - 1.1 kg
u1 = 292 m/s u2 = 0
v1 = 274 m/s v2 = ?
(0.012*292)+(0) = (0.012*274)+(1.1*v2)
v2 = 0.196 m/s
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