A)what is the balanced reaction between barium hydroxide and hydorochloric acid?
ID: 850956 • Letter: A
Question
A)what is the balanced reaction between barium hydroxide and hydorochloric acid?
B) Calculate the molarity of a barium hydroxide solution if a 55.00 mL portion of this solution is nutralized by 55.00mL of 0.5000 M HCL?
C) In Standardizing a potassium hyroxide solution, a student finds that 24.55mL of the base solution is needed to titrate 0.5002 gram of KHP to a phenolphthalein end point. In another titration, 29.40 mL of this same base solution is needed to titrate 0.2777 grams of an unknown solid monoprotic acid.Determine the molarity of the base solution and determine the molar mass of the unknown solid monoprotic acid.
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Explanation / Answer
A)
Ba(OH)2 + 2Hcl ----> BaCl2 + 2H20
B)
from the reaction
moles of HCl = 2 x moles of Ba(OH)2
we konw that
moles = molarity x volume
so
molarity x volume of HCl = 2 x molarity x volume of Ba(OH)2
0.5 x 55 = 2 x M x 55
M = 0.25
so
molarity of Ba(OH)2 is 0.25 M
C)
moles = mass / molar mass
moles of KHp = 0.5002 / 204.22
moles of KHP = 2.45 x 10-3
the reaction is
KHP + KOH ---> K2P + H20
so
moles of KOH = moles of KHP
moles of KOH = 2.45 x 10-3
we know that
moles = molarity x volume ( L)
2.45 x 10-3 = molarity x 24.55 x 10-3
molarity of KOH = 0.0998 M
now
KOH + HA ---> KA + H20
moles of HA = moles of KOH
given 29.40 ml of KOH
so
moles = molarity x volume (L)
moles of KOH = 0.0998 x 29.40 x 10-3
moles of KOH = 2.934 x 10-3
so
moles of HA = 2.934 x 10-3
mass of HA / molar mass = 2.934 x 10-3
0.2777 / molar mass = 2.934 x 10-3
molar mass = 94.65
so the molar mass of unknow acid is 94.65 g
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