A)Two individuals are going to reproduce. THey are both heterozygous for a fene

Question

A)Two individuals are going to reproduce. THey are both heterozygous for a fene of interest (Bb). Write below a Punnett square analysis to show the genotypes of the offspring they can produce.

B)Based upon the punnett square, what is the relative frequency of each genotype

C)Assume complete dominance and that B is the allele for dark hair and b the allele for light hair. Based upton the punnett square based on question a, what are the possible pphenotypes for each genotype possible in the offspring? What is the relative frequency of each phenotype ?

Explanation / Answer

A) B b B BB Bb b Bb bb b) the frequency of homozygous genotype is 50% ie BB and bb the frequence of heterozygous genotype is 50% ie Bb BB - 25% Bb - 50% bb - 25% c) B = dark hair ; b = light hair. BB, Bb, Bb show dark hair, since they have B, dominant genotype... 75% bb offspring will have light hair. 50%

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.