For a glucose concentration, let\'s use 1.0 mM (0.0010 mmol/L). (This is a reali

Question

For a glucose concentration, let's use 1.0 mM (0.0010 mmol/L). (This is a realistic value, by the way.) You have used the value of Avogadro's number in Sapling Learning and should be able to easily recover it in any of several ways. Also, you may need the fact that 1 cubic centimeter (1 cm3) is equal to 1 mL. Let's imagine a cell that is a cube, 0.010 cm on each edge. (This would be a very large cell.) How many glucose molecules would there be in this "cell"?

A. 33 x 10^(11)

B. 3.3 x 10^(10)

C. 6 x 10^(11)

D. 6 x 10^(10)

Explanation / Answer

Vol of cell = (0.01cm)3 = 10-6 cm3 = 10-6 ml

Now Conc. of glucose = 0.0010 mmol/L = 0.0000010 mmol/L (recall 1L = 1000ml ) = 10-6 mol glucose per ml.

Therefore in 10-6 ml (The volume of 1 cwel), the amount of glucose will be

10-6 mol glucose per ml x 10-6 ml = 10-12 mol glucose

Now, 1 mole =6x1023 molecules of glucose

so, no.of olecules of glucose present = 10-12 mol glucose x 6x1023 = 6 x 10^(11) molecules

So, option c is correct

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