HELP! 1.If 10.0 grams of calcium chloride are dissolved in water to make 75.0 mi

Question

HELP!

1.If 10.0 grams of calcium chloride are dissolved in water to make 75.0 milliliters of a solution what is the molar concentration of the solution?

I know the answer is 1.20 but I need to know how to get that

2. How many milliliters of a 2.00 M sodium hydroxide solution are necessary to completely neutralize 50.0 milliliters of a 1.25 M sulfuric acid solution?

I know the answer is 62.5 but I need to know how

3. What is the maximum mass of precipitate that can form from a solution made by mixing 25.0 milliliters of 0.125 M sodium carbonate with an excess of 0.150 M calcium nitrate?

Answer 0.313 grams but I need to know how to get that

Explanation / Answer

1)molar mass of CaCl2=110

molarity=moles/volume in litres=(10/111)/0.075=1.201

2)N1*V1=N2*V2

now since H2SO4 has two hydrogen ions

2*x=2*1.25*50

x=62.5ml

3)for 0.15 mole CaCO3 u need 0.15 moles of carbonate ion but u have only 0.125 moles of carbonate.so only 0.125 moles of CaCO3 will be formed

mass=volume*molarity*molar mass of CaCO3=0.125*0.025*100=0.3125g

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