One method for neutralizing streams that are polluted by acid mine drainage (aci

Question

One method for neutralizing streams that are polluted by acid mine drainage (acids that drain out of abandoned mines) is to treat the polluted streams with limestone, CaC)3. The Net Iconic equation is:

2H^+1 + CO3^-2 -----> CO2 + H2O

If the average hydrogen ion concentration in a polluted stream is 8.15*10^-4 moles per liter of stream solution, how many liters of the stream solution can be neutralized per ton of limestone that is 95% pure? (1 ton = 908 kg, molecular weight of CaCO3 is 100 g/mole) Assume the reaction goes to completion

Explanation / Answer

concentration of hydrogen = 8.15*10-4M

weight of CaCO3 = 0.95 *908 = 862.6 kg

no of moles of CaCO3= 862.6*1000/100 = 8626 moles

1 mole neutralizes 2 moles of H+

8626 moles neutralizes 17252 moles of H+

no of litres of stream solution that can be neutralised = 17252/( 8.15*10-4) = 2116.81 *104 Litres

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