One long wire carries current 12.0 A to the left along the x axis. A second long

Question

One long wire carries current 12.0 A to the left along the x axis. A second long wire carries current 76.0 A to the right along the line (y = 0.280 m, z = 0).

(b) A particle with a charge of ?2.00

One long wire carries current 12.0 A to the left along the x axis. A second long wire carries current 76.0 A to the right along the line (y = 0.280 m, z = 0). A particle with a charge of ?2.00 Mu C is moving with a velocity of 150i Mm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle.

Explanation / Answer

a) y = - 0.165 m (ie parallel to the x-axis)

b) B1 = (mu/(2 pi)) 54 A/0.18 m = 300 (mu/(2 pi)) T along -z axis
B2 = (mu/(2 pi)) 20 A/ 0.1 m = 200 (mu/(2 pi)) T along + z axis

Net B = 100 (mu/(2 pi)) T = 100 (2 10^-7) T = 2 10^-5 T along - z-axis

Force = q v x B = (-2 10^-6 C) (150 10^-3 m/s) (2 10^-5 T) = 6*10^(-12) N along the -y axis

That should allow you to calculate the electric field to balance that force. E = F/q

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