For the reaction described by the following chemical equation: 3C2H2(g) --------

Question

For the reaction described by the following chemical equation:

3C2H2(g) -----------------------> C6H6 (l)    Delta H rxn = -633.1 Kj*Mol^-1

Where

      Delta Hf                   Delta Gf                 S

C2H2 227.4                      209.9                    200.9

C6H6 49.1                        124.5                     173.4

1. Calculate: Delta Srxn = ? J*K^-1*mol^-1

2. Calculate: Delta Grxn = ? Kj *Mol ^-1

3. In which direction is the reaction as written spontaneous at 25 C and standard pressure: forwards, reverse, bothe or neither?

Explanation / Answer

1) Delta Srxn = 173.4-3*200.9 = -429.3

2)Delta Grxn=124.5-3*209.9= -505.2

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