For the reaction CO+1/2O2=CO2, what is the enthalpy of reaction H at 298K? For t

Question

For the reaction CO+1/2O2=CO2, what is the enthalpy of reaction H at 298K?

For the reaction CO+1/2O_2 = CO_2, what is the enthalpy of reaction delta H degree at 298K? A fuel gas with composition 50%CO, 50%N_2 is burned using the stoichiometric amount of air What is the composition of the flue gas? If the fuel gas and the air enter the burner at 298 K, what is the highest temperature the flame may attain (adiabatic flame temperature)? Standard heats of formation delta H degree_f at 298K. CO = -110,000 (J/mol) CO_2 = -393,000 (J/mol)

Explanation / Answer

Standard enthalpy of formation values will be calculated at 298 K and 1 atm.

CO (g) +1/2 O2 (g) -----------------> CO2 (g)

We know that

Hof CO2 (g) = - 393.5 kJ/mol

Hof CO(g) = - 110.5 kJ/mol

Hof O2(g) = 0

Ho = Hof of products - Hof of reactants

      = Hof CO2 (g) - [ Hof CO(g) + (1/2) Hof O2(g) ]

      = -393.5 kJ/mol - [ -110.5 kJ/mol + (1/2) x 0] kJ/mol

     = - 283.0 kJ/mol

  Ho = - 283.0 kJ/mol

Therefore,

Enthalpy of reaction H at 298K = - 283.0 kJ/mol

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