For the reaction 2NO_2(g) rightarrow 2NO(g) + O_2(g) initial rate = k[NO_2]O^2.

Question

For the reaction 2NO_2(g) rightarrow 2NO(g) + O_2(g) initial rate = k[NO_2]O^2. For concentration in M and time in s, the units of the rate constant k are M^-2 s^-1 M^-1 s^-1 s^-1 M^-2 s^-1 M s^-1 s^-1 Given: 2N_2O5(g) rightarrow 4NO_2(g) + O_2(g) rate = k[N_2O_5] The overall order of the reaction is 1 0 2 3 7 The reaction 2NO(g) + Br_2(g) rightarrow 2NOBr(g) is second-order in NO and first-order in Br_2. If the initial concentrations of NO and Br_2 are 0.0200 M and 0.0100 M, respectively, the rate after 50% of the Br2 has reacted is what percent of the initial rate? 12.5% 37.5% 18.8% 2.50% 50.0% A first-order reaction has a rate constant of 0.00300 s^-1. The time required for 75% reaction is 231s 201s 41.7 s 462 s 95.9 s

Explanation / Answer

5)

rate constant K

must be equal to

Rate = k(NO2)^2

rate = mol/L-s

Concnetratin is always measured in mol/L

so

Rate = K*(NO2^2)

solve for K

K = Rate /(NO2^2)

substitute dimensions

K = (mol/L-s)/(mol/L)^2

K = (mol/L-s)/(mol^2/L^2)

K = L/(mol-s)

or

K = 1/(M-s)

K = M^-1 s^-1answer must be B

6)

Since rate depends only to one concnetration and to power 1

n = 1+0 = 1

rate is first order

NOTE: Please consider posting multiple questions in multiple set of Q&A. We are not allowed to answer to multiple questions in a single set of Q&A

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.