The activation energy of a certain reaction is 49.8 k J / m o l . At 30 ? C , th

Question

The activation energy of a certain reaction is 49.8kJ/mol . At 30 ?C , the rate constant is 0.0160s?1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T2 = SubmitHintsMy AnswersGive UpReview Part Part B Given that the initial rate constant is 0.0160s?1 at an initial temperature of 30 ?C , what would the rate constant be at a temperature of 190 ?C for the same reaction described in Part A? Express your answer with the appropriate units. k2 = The activation energy of a certain reaction is 49.8kJ/mol . At 30 ?C , the rate constant is 0.0160s?1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T2 = SubmitHintsMy AnswersGive UpReview Part The activation energy of a certain reaction is 49.8kJ/mol . At 30 ?C , the rate constant is 0.0160s?1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T2 = SubmitHintsMy AnswersGive UpReview Part T2 = T2 = SubmitHintsMy AnswersGive UpReview Part Part B Given that the initial rate constant is 0.0160s?1 at an initial temperature of 30 ?C , what would the rate constant be at a temperature of 190 ?C for the same reaction described in Part A? Express your answer with the appropriate units. k2 = Part B Given that the initial rate constant is 0.0160s?1 at an initial temperature of 30 ?C , what would the rate constant be at a temperature of 190 ?C for the same reaction described in Part A? Express your answer with the appropriate units. k2 = k2 = k2 = T2 =

Explanation / Answer

1)

log(k2/k1) = Ea/(2.303*R) [ 1/T1 - 1/T2]

given : k2 = 2*k1 and Ea =49.8 Kj/mol T =30+273 = 303 K and let T be the temp.

so

log 2 = 49.8*1000/2.303*8.314 *[1/303-1/T]

T = 314.01 K = 41.01 deg. celsius

2) now k at T = 90 +273 K = 363 K

log(k/0.016) = 49.8*1000/2.303*8.314* [1/303-1/363]

k =0.419 s^-1

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