Box Depth (m) Velocity (m/s) Width (m) Area (m 2 ) (width*depth) Discharge (m 3
ID: 804056 • Letter: B
Question
Box
Depth (m)
Velocity (m/s)
Width (m)
Area (m2)(width*depth)
Discharge (m3/s)
(A*V
A
0.60
0.05
0.5
0.30
0.015
B
0.73
0.22
0.5
C
0.81
0.39
0.5
D
0.85
0.45
0.5
E
0.90
0.55
0.5
F
0.87
0.51
0.5
G
0.83
0.53
0.5
H
0.80
0.44
0.5
I
0.76
0.37
0.5
J
0.73
0.29
0.5
K
0.68
0.22
0.5
L
0.64
0.05
0.5
M
0.20
-0.01
0.35
TOTAL:
4. The rational method of runoff determination is best used for small watersheds. The equation is:
Q = CiA where Qp = peak runoff rate (cfs); C = runoff coefficient; i = peak rainfall intensity (in/hr)
A = drainage area (acres).
Please answer questions 3&4
3. Below is drawn a cross-section through a river, with the flow towards you. You are hired to calculate the discharge at this site. You divide the stream into sections, each evenly spaced 0.5 m apart, except for the last section (M) which is 0.35 wide. Calculate the cross-sectional area and discharges for each section as well as the total area and discharge. Calculate the area of each “box” bymultiplying width by depth. Calculate the discharge as area multiplied by velocity, and then total the discharge. I’ve done the first one to help.
Explanation / Answer
Please answer questions 3&4
3. Below is drawn a cross-section through a river, with the flow towards you. You are hired to calculate the discharge at this site. You divide the stream into sections, each evenly spaced 0.5 m apart, except for the last section (M) which is 0.35 wide. Calculate the cross-sectional area and discharges for each section as well as the total area and discharge. Calculate the area of each “box” bymultiplying width by depth. Calculate the discharge as area multiplied by velocity, and then total the discharge. I’ve done the first one to help.
Box
Depth (m)
Velocity (m/s)
Width (m)
Area (m2)(width*depth)
Discharge (m3/s)
(A*V
A
0.60
0.05
0.5
0.30
0.015
B
0.73
0.22
0.5
0.36
0.080
C
0.81
0.39
0.5
0.40
0.157
D
0.85
0.45
0.5
0.42
0.189
E
0.90
0.55
0.5
0.45
0.247
F
0.87
0.51
0.5
0.43
0.221
G
0.83
0.53
0.5
0.41
0.219
H
0.80
0.44
0.5
0.40
0.176
I
0.76
0.37
0.5
0.38
0.140
J
0.73
0.29
0.5
0.36
0.105
K
0.68
0.22
0.5
0.34
0.074
L
0.64
0.05
0.5
0.33
0.016
M
0.20
-0.01
0.35
0.07
0.0007
TOTAL:
1.6397
4. The rational method of runoff determination is best used for small watersheds. The equation is:
Q = CiA where Qp = peak runoff rate (cfs); C = runoff coefficient; i = peak rainfall intensity (in/hr)
A = drainage area (acres).
A. What would the runoff be if a 3 acre watershed got 10 in/hr rainfall and an average c coefficient of 0.4?
Run-off equation = Qp = CiA C= run off coeffeceient = 0.4
i=peak rain fall = 10in/hr
A= drainage area (acres)=3.0acres
Then Run off Qp =0.4 x 10 x 3 = 12
B. Same rainfall, but half (1.5 acres) of the watershed is urbanized (c=0.8) and half (1.5) of the watershed is forest (c=0.2)?
A=1.5 acres urbanized area
C=0.8
i = 10in/hr
Then Run off Qp = 0.8 x 10x 1.5 = 12in
A=1.5 acres forest area
C=0.2
i=10in/hr
Then Run off Qp =0.2 x 10 x 1.5 =3in
C. What is Q if that same watershed then completely urbanizes and now has a c value of 0.8? What would this due to the risk of flooding in the watershed?
A= 3 acres entire watershed urbanized
C=0.8
i = 10in/hr
Then Run off Qp = 0.8 x 10 x 3 = 24in
Yes run off 24 in means its due to flooding of the watershed
Please answer questions 3&4
3. Below is drawn a cross-section through a river, with the flow towards you. You are hired to calculate the discharge at this site. You divide the stream into sections, each evenly spaced 0.5 m apart, except for the last section (M) which is 0.35 wide. Calculate the cross-sectional area and discharges for each section as well as the total area and discharge. Calculate the area of each “box” bymultiplying width by depth. Calculate the discharge as area multiplied by velocity, and then total the discharge. I’ve done the first one to help.
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