PLEASE SHOW WORK! 2. You have built the electrolytic cell below. a) Write the ch

Question

PLEASE SHOW WORK!

2. You have built the electrolytic cell below.

a) Write the chemical equation for the anodic and cathodic processes. What is the overall reaction?

b) How many moles/grams of oxygen and hydrogen are produced after 5 min of electrolysis at a current of 0.23 A? What is the volume of the gases at room temperature and atmospheric pressure (assume ideal gas law). What is the total number of electrons that passed the electrode/electrolyte interface?

4. Calculate the potential in the following cell

Zn|Zn2+(1.00M)|| Cu2+(1.00M) |Cu

a) right at the beginning when you start using this voltaic cell,

b) when 50% of the Cu2+ ions have been consumed,

c) when 99% of the Cu2+ ions have been consumed, and

d) when 99.99% of the Cu2+ ions have been consumed.

Keep in mind that both, the Zn2+ and the Cu2+ concentrations are changing.

Picture of th circut for question 2.

You have built the electrolytic cell below. Write the chemical equation for the anodic and cathodic processes. What is the overall reaction? How many moles/grams of oxygen and hydrogen are produced after 5 min of electrolysis at a current of 0.23 A? What is the volume of the gases at room temperature and atmospheric pressure (assume ideal gas law). What is the total number of electrons that passed the electrode/electrolyte interface? Calculate the potential in the following cell Zn|Zn2+(1.00M)|| Cu2+(1.00M) |Cu right at the beginning when you start using this voltaic cell, when 50% of the Cu2+ ions have been consumed, when 99% of the Cu2+ ions have been consumed, and when 99.99% of the Cu2+ ions have been consumed. Keep in mind that both, the Zn2+ and the Cu2+ concentrations are changing.

Explanation / Answer

2

a) Cathode (reduction): 2 H2O(l) + 2e? ? H2(g) + 2 OH-(aq)

Combining either half reaction pair yields the same overall decomposition of water into oxygen and hydrogen:

b)

96,500 C produces 1mole of substance.

Charge input= (0.23 x 300) C

                       = 69 C

96500 C produces 2 moles of H2

Thus, 69 C produces = (2/96500) x 69 C

                                     = 1.43 x 10-3 moles

96500 C produces 1 mole of H2

Thus, 69 C produces = (1/96500) x 69 C

                                     = 7.15 x 10-4 moles

4)

Zn2+ + 2e-----> Zn   -0.7628V

Cu2+ + 2e- ---

4)

Zn2+ + 2e-----> Zn   -0.7628V

Cu2+ + 2e- ---

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