2 PART QUESTION.. WILL GIVE OUT 600 POINTS. For the gaseous reaction shown here,

Question

2 PART QUESTION.. WILL GIVE OUT 600 POINTS.

For the gaseous reaction shown here, the bins below represent three different possibilities for the equilibrium mixture. Classify each mixture by what it indicates about , K, and lnK for the reaction at standard conditions. Drag the appropriate items to their respective bins. The image represents a spontaneous, gaseous reaction at a constant temperature T K. Predict whether , , and for this reaction are positive, negative, or zero. Drag the appropriate items to their respective bins.

Explanation / Answer

delta G = delta H - ( t x delta S)

delta G = - n x R x T x ln K

mix 1 :

delta G > 0

ln K < 0

K < 1

mix 2 :

delta G =0

ln k =0

K=1

mix 3 :

delta G < 0

ln K > 0

k > 1

2)

Here the randomness decreased

therefore delta S is negative

therefore the term - ( T x delta S ) becomes positive.

spontaneous process therefore delta G is negative

to balance this it shows delta H is negative

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.