1) 0.90 g of hydrogen chloride ( H C l ) is dissolved in water to make 2.5 L of
ID: 795011 • Letter: 1
Question
1)
0.90g of hydrogen chloride (HCl) is dissolved in water to make 2.5L of solution. What is the pH of the resulting hydrochloric acid solution?
Kw=[H=][OH-]=1.00*10^-14
2)
0.40g of sodium hydroxide (NaOH) pellets are dissolved in water to make 5.0L of solution. What is the pH of this solution?
Kw=[H=][OH-]=1.00*10^-14
Explanation / Answer
no. of moles of HCl= 0.9/36.5 = 0.025 moles
molarity of the solution= .025/2.5 = 0.01M
molarity of hydronium ion= 0.01M
pH of the solution= -log(0.01) = 2 (answer)
no. of moles of NaOH= 0.4/40 = 0.01 moles
molarity of the solution= .01/5 = 0.002M
molarity of hydroxyl ion= 0.002M
pOH of the solution= -log(0.002) = 2.7
i.e., pH of the solution= 14-2.7 = 11.3 (answer)
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