1) (8 pts) A large reservoir exists at an elevation of 98 ft. A pump is required

Question

1) (8 pts) A large reservoir exists at an elevation of 98 ft. A pump is required to move 240 gallons per minute of water from it to a reservoir located at an elevation of 250 ft. What is the power of the pump in horsepower? 2) (12 pts) Between a 100 mm diameter suction pipe and a 75 mm diameter discharge pipe lies a pump. 32 L/s of water flow through the system. At a point on the suction pipe, a vacuum gauge reads 150 mm of mercury. At a point 3.6 m above, the pressure gauge on the discharge pipe is 331 kPa. At these conditions, the specific gravity of mercury is 13.57. What is the power of the pump in kw? 3) A pump takes water from a tank and discharges it into the atmosphere through a horizontal 50-m nozzle. The nozzle is 4.5 meters above the water surface and is connected to the pump's 100 mm diameter discharge pipe 4.5M a) (9 pts) To maintain a pressure of 276 kPa just upstream from the nozzle, what power must the pump have in kw? b) (3 pts) Sketch the system and draw the energy and hydraulic grade lines. 4) (10 pts) water flows through a tee in a horizontal pipe system. The velocity in the stem of the tee is 15 feet per second, and the diameter is 12 inches. Each branch is of 6 inches diameter If the pressure in the stem is 20 psi, calculate the magnitude and direction of the force of the water on the tee if the flowrates in the branches are the same St 5) (14 pts) Water flows from a 2-d open channel and is 0% diverted by an inclined plane as shown at right. When the velocity at section 1 is 10 ft/s, what horizontal force per unit width (in lb) is required to hold the plane in place? Assume that the pressure distribution is hydrostatic at section 1 and that the fluid acts as a free jet at section 2. Neglect friction. 6) (14 pts) An air curtain is used to separate a loading dock from a cold storage room. The air curtain is a jet of air 10 feet wide and 0.5 feet thick that moves with a speed of 30 ft/s a negligible distance from the top of the curtain. The loss associated with this flow is estimated as K V2/(2g), where KL equals 5 How much power is required by a fan to produce this flow of air? N:30 5

Explanation / Answer

1.

Solution :

To lift " m " mass of water through a height "h" energy required is given by

E = mgh

We have to lift 240 gallons = 32.08 ft3 of water

In terms of mass(m) = 2002.69 pounds (using density of water as 62.428 pounds/ft3 )

h = height = 250-98 = 152 ft

g = 32.174 ft/s2

So

E = 2002.69 * 32.174 * 152 = 9794051.31 lb ft2/s2

As this much energy has to be given in a minute so power of pump is

P = E/t = 9794051.31/60 = 163234.188 lb ft2 /s3

Or in HP we have 163234.188/17696 = 9.22 hp .............Answer

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