1) 07How many grams of Li3N can be formed from 1 75 moles of Li? Assume an exces
ID: 229482 • Letter: 1
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1) 07How many grams of Li3N can be formed from 1 75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) 2 Li3N(s) A) 183 g LighN B) 610 g LigN ) 20.3 g Li3N D) 58.3 g LigN E) 15.1 g Li3N 2)How many moles of nitrogen are formed when 58.6 g of KNO3 decomposes according to the 2) following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNOg(s) 2 K20(s) + 2 N2(g) + 5O2(g) A) 1.73 mol N2 B) 0.580 mol N2 C) 0.290 mol N2 D) 0.724 mol N2 E) 18.5 mol N2 3) Give the percent yield when 28.16 g of Co2 are formed from the reaction of 7.000 moles of CsH1s 3) with 14.00 moles of O2. 2C8H18 + 252 16CO2 + 18H20 A) 11.42% B) 14.28% 39.00 D) 2856% E) 7.140% 4) How many milliliters of a 0.184 M KNO3 solution contain 0.113 moles of KNO3? 4) D) 885 mL E) 163 mL 326 mL 5) How many milliliters of a 0.266 M KNOs solution are required to make 150.0 mL of 0.075 M KNOs 5) C) 18.8 mL A) 614 mL B) 543 mL solution? A) 53.2 mL B) 35.1 mL D) 23.6 mL E) 42.3 mL 6How many liters of a 0.0550 M NaF solution contain 0.163 moles of NaF? 6) A) 3.37 L B) 1.12 L 148L D) 8.97 L E) 296 L 7 What is the concentration of barium ions in a 0.750 M BaCl2 solution? 7) A) 2.25 M B) 0.160 M 150 M D) 0.375 M E) 0.750 MExplanation / Answer
1) 6 mol Li = 1 mol N2 = 2 mol Li3N
No of mol of Li taken = 1.75 mol
N2 = excess,
limiting reactant = Li
No of mol of Li3N produced = 1.75*2/6 = 0.583 mol
amount of Li3N produced = N*molarmass
= 0.583*35
= 20.4 g
answer: C
2) 4 mol KNO3 = 2 mol N2
No of mol of kno3 taken = 58.6/101.11 = 0.58 mol
No of mol of N2 formed = 0.58*2/4 = 0.29 mol
answer: C
3) 2 mol c8h18 = 25 mol o2 = 16 mol co2
no of mol of c8h18 taken = 7 mol
no of mol of O2 = 14 mol
limiting reactant = o2
no of mol of co2 produced = 14*16/25 = 8.96 mol
theoretical yield = 8.96*44 = 394.24 g
percent yield= actual yield/theoretical yield*100
= 28.16/394.24*100
= 7.14%
answer: E
4) No of mol of KNO3 = Molarity*Volume
volume = 0.113/0.184 = 0.614 L
= 614 ml
answer: A
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