Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous

Question

Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 6.9 g of sulfuric acid is mixed with 3.92 g of sodium hydroxide.
Calculate the maximum mass of sodium sulfate that could be produced by the chemical reaction. Round your answer to significant digits. Aqueous sulfuric acid (H2SO4) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na2SO4) and liquid water (H2O). Suppose 6.9 g of sulfuric acid is mixed with 3.92 g of sodium hydroxide. Calculate the maximum mass of sodium sulfate that could be produced by the chemical reaction. Round your answer to 3significant digits.

Explanation / Answer

H2SO4+2NaOH---->Na2SO4+2H2O

So 1 mole of H2SO4 reacts with 2 moles of NaOH to produce 1 mole of Na2SO4 and 2 moles of H2O

6.9g H2SO4=6.9/98=0.0704 moles

3.92 g NaOH=3.92/40=0.098 moles

Hence NaOH is the limiting reagent and it reacts with (0.098/2)=0.049 moles H2SO4 to produce 0.049 moles Na2SO4

Mass of Na2SO4=0.049x142

=6.96 g

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