For the reaction, calculate how many grams of the product form when 2.6g of Cl2

Question

For the reaction, calculate how many grams of the product form when 2.6g of Cl2 completely reacts 2Na(s)+Cl 2 (g)?2NaCl(s) For the reaction, calculate how many grams of the product form when 2.6g of CaO completely reacts CaO(s)+CO 2 (g)?CaCO 3 (s) For the reaction, calculate how many grams of the product form when 2.6g m g of Mg m Mg completely reacts. 2Mg(s)+O 2 (g)?2MgO(s) For the reaction, calculate how many grams of the product form when 2.6g of Na2O completely reacts Na 2 O(s)+H 2 O(l)?2NaOH(aq) Hydrochloric acid can dissolve solid iron according to the following reaction. Fe(s)+2HCl(aq)?FeCl 2 (aq)+H 2 (g) 1. What minimum mass of HCl in grams would you need to dissolve a 2.8g iron bar on a padlock? 2. How much H2 would be produced by the complete reaction of the iron bar?

Explanation / Answer

2Na(s)+Cl 2 (g)---->2NaCl(s)

moles of Cl2 = 2.6/71 = 0.0366

so moles of NaCL = 2*0.0366 = 0.0732

so mass = 0.0732*58.5 = 4.2822 gm

CaO(s)+CO 2 (g)--->CaCO 3 (s)

moles of CaO = 2.6/56 = 0.046

so moles of CaCO3 = 0.046

so mass = 4.6 gm

2Mg + O2 ---> 2MgO

moles of Mg = 2.6/24 = 0.108

so moles of MgO = 0.108

so mass = 0.108*40 = 4.32 gm

Na 2 O(s)+H 2 O(l) ----> 2NaOH(aq)

moles of Na2O = 2.6/62 = 0.042

so moles of NaOH = 2*0.042 = 0.084

so mass = 0.084*40 = 3.36 gm

Fe(s)+2HCl(aq) ----> FeCl 2 (aq)+H 2 (g)

mass of Fe = 2.6 gm

so moles = 2.6/55.8 = 0.0466

so moles of HCl required = 2*0.0466 = 0.0932

so mass = 0.0932*36.5 = 3.4018gm

moles of H2 = 0.0466

so mass = 0.0466*2 =0.0932 gm

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