Balance the following equation: Pb(NO 3 ) 2 (aq) + Na 3 PO 4 (aq) %u2192 Pb 3 (P

3 Pb(NO3)2(aq) + 2 Na3PO4(aq) = Pb3(PO4)2(s) + 6 NaNO3(aq) this is the balanced chemical reaction.

ID: 779364 • Letter: B

Question

Balance the following equation:

Pb(NO3)2(aq) + Na3PO4(aq) %u2192 Pb3(PO4)2(s) + NaNO3(aq)

Using the balanced equation, starting concentrations and the initial volumes, determine the limiting reagent for this part.

Notes for calculation purposes:

1. Assume 20 drops = 1 mL.

2. Report all answers to two significant figures.

Initial moles Pb(NO3)2 = mol

Initial moles Na3PO4 = mol

Number of moles of Pb3(PO4)2 that can be formed from each starting reagent is:

from Pb(NO3)2 = mol Pb3(PO4)2

from Na3PO4 = mol Pb3(PO4)2

Give the chemical formula for the starting solution that was the limiting reagent

3 Pb(NO3)2(aq) + 2 Na3PO4(aq) = Pb3(PO4)2(s) + 6 NaNO3(aq)

this is the balanced chemical reaction.

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.