Balance the 2 following equations.....then identify the oxidation half reaction

Question

Balance the 2 following equations.....then identify the oxidation half reaction and the reduction half reaction.
1. Fe2+ +MnO4- ---> Fe3+ +Mn2+ acidic solution

2. NO3- +Cu---> NO + Cu2+

Explanation / Answer

Fe2+(aq) + MnO4-(aq) ---> Fe3+(aq) + Mn2+(aq) (acidic solution) to balance this... 1. Write the half reactions: Fe2+(aq) ---> Fe3+(aq) (oxidation) MnO4-(aq) ---> Mn2+(aq) (reduction) 2. Balance each half reaction: Fe2+(aq) ---> Fe3+(aq) + e- MnO4-(aq) + 8H+(aq) + 5e- ---> Mn2+(aq) + 4H2O 3. Combine the half reactions to give the overall reaction: 5Fe2+(aq) ---> 5Fe3+(aq) + 5e- MnO4-(aq) + 8H+(aq) + 5e- ---> Mn2+(aq) + 4H2O ----------------------------------------… 5Fe2+(aq) + MnO4-(aq) + 8H+(aq) ---> 5Fe3+(aq) + Mn2+(aq) + 4H2O Cu = Cu2+ + 2e- ) x 3 NO3- + 4 H+ + 3e- = NO + 2 H2O ) x 2 3 Cu + 2 NO3- + 8 H+ = 3 Cu2+ + 2 NO + 4 H2O

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