Item 5 5 of 11 Constants Periodic Table Part A A neutron (mass 1.01 u) strikes a

Question

Item 5 5 of 11 Constants Periodic Table Part A A neutron (mass 1.01 u) strikes a deuteron (mass 2.01 u), and they combine to form a tritium nucleus (mass 3.02 u). The neutron's initial velocity was 13.3 i 11.5j+ 44.3 k Mm/s and the tritium nucleus leaves the reaction with velocity 17.8i 22.4 k Mm/s What was the deuteron's velocity? Enter the x, y and z vector components separated by commas Wg Uys 22.3, -5.78,11.4 Mm/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Provide Feedback Next

Explanation / Answer

Applying conservation of momentum we have

Momentum before collision = Momentum after collision

Momentum of neutron + Momentum of deutron = Momentum of Tritium

1.01 ( 13 i +11.5 j + 44.3 k) + 2.01 v = 3.02 (17.8i +22.4 k)

13.13 i + 11.62 j + 44.74 k + 2.01v = 53.76 i + 67.65 k

2.01 v = 53.76 i - 13.13i -11.62 j + 67.65 k - 44.74k

2.01 v = 40.63 i - 11.62 j + 22.91 k

v = 20.21 i - 5.78 j +11.39 k

answer: 20.21, -5.78 , 11.39

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