Item 2 Part A The solubility of gas in a liquid is profoundly affected by pressu

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Item 2 Part A The solubility of gas in a liquid is profoundly affected by pressure. This relation is expressed by Henry's law, which states that the solubility of a gas in a liquid, expressed in moles per liter (or M), at a given temperature is directly proportional to the partial pressure of the gas over the solution. This relation can be expressed mathematically as Air is a mixture of gases that is about 78.0% N2 by volume. When air is at standard pressure and 250°C, the N2 component will dissolve in water with a solubility of 4.88 × 10-4 M. What is the value of Henry's law constant for N2 under these conditions? Express your answer with the appropriate units. Enter the unit M using the compound form mo/L Hints solubility = k-P The constant k is characteristic of the specific gas and P is the partial pressure of the gas over the solution usually expressed in atmospheres. The constant k usually has units of moles per liter per atmosphere and is reported at 25 °C. This expression can be used to calculate any of the three variables provided that the other two are known for any gas ValueUnits k= Submit My Answers Give Up

Explanation / Answer

partial pressure of air = mole fraction* total pressure= 0.78*1 =0.78 atm

K= Henry's law constant = solubility/partial pressure = 4.88*10-4/0.78 M/atm =0.000626 M/atm

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