Item 11 The average power dissipated by a resistor connected to a sinusoidal emf

Question

Item 11 The average power dissipated by a resistor connected to a sinusoidal emf is 4.0W. Part A What is Pavg if the resistance R is doubled? Express your answer to two significant figures and include the appropriate units. Pavg = Value Units Part B What is Pavg if the peak emf epsilon0 is doubled? Express your answer to two significant figures and include the appropriate units. Pavg= Value Units Part C What is Pavg if both are doubled simultaneously? Express your answer to two significant figures and include the appropriate units. Pavg = Value Units

Explanation / Answer

Part A

if Resistance is doubled

then Pav=V^2/R

so 4=V^2/R

V^2=4R--1

so if resistance is doubled then

Pav=V^2/R

putting value of 1 in this equation

Pav=4R/2R

Pav=2 watt

Part B

Pav=2V^2/R

Pav=2*4R/R

Pav=8 watt

here power gets doubled

Part C

Pav=2V^2/2R

=V^2/R

=4R/R

=4 watt

power remains same in this case

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.