Dear Tutor I have already asked this question but the answer I got was only for

Question

Dear Tutor

I have already asked this question but the answer I got was only for path 1. It would be much appreciated if I could get an answer for path 2.

One mole of an ideal monatomic gas is taken from state A to state B by two different paths (path 1 and path 2). For each segment of each path evaluate the work done on or by the gas, the heat added to or removed from the gas, and the change in internal energy. Express your answers in terms of RTA where TA is the temperature at point A.

Summarize the overall results in a table as below:

Explanation / Answer

from ideal gas equation

PA*VA/TA = PB*VB/TB

P1*V1/TA = 2P1*4V1/TB

TB = 8*TA

---

P1*V1 = n*R*TA

P1*V1 = 1*R*TA

work done in path 2a , W2a = area of trapezium = (P1+3P1)*V1/2 = 2*p1*V1

work done in path 2b , W2b = area of rectangle = (3V-2V1)*3P1 = 3*p1*V1

work done in path 2c , W2c = area of trapezium = (2P1+3P1)*(4V1-3v1)/2 = 2.5*p1*V1

total work done W = 7.5*p1*V1 = 7.5*R*TA

change in internal energy dU = n*Cv*dT = n*(3/2)*R*(TB - TA) = 1*(3/2)*(8TA-TA) = 10.5*R*TA

from Ist law of thermodynamics

Q = dU + W

Q = 18*R*TA

Q = 18*R*TA

W = 7.5*R*TA

dU = 10.5*R*TA

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.