3)The data in the table below were obtained for the reaction: A + B ----> P Use
ID: 767815 • Letter: 3
Question
3)The data in the table below were obtained for the reaction: A + B ----> P Use this info for quest 3 and 4.
3) Write the rate law for this reaction
4) Calculate the magnitude of the rate constant (with units) please include explanation I appreciate it and will rate well thank you and solved for me so that I may understand for my test please. I get confused on how to get the rate law
Experiment
[A} [M]
[B] [M]
Initial rate
1
0.273
0.763
2.83
2
0.273
1.526
2.83
3
0.819
0.763
24.47
Experiment
[A} [M]
[B] [M]
Initial rate
1
0.273
0.763
2.83
2
0.273
1.526
2.83
3
0.819
0.763
24.47
Explanation / Answer
3) The rate law of reaction mentioned in the problem is rate=k [A]^m x [B]^n, where m and n are order with respect to reactants A and B. In order to find the value of m, that is order with respect to A, search two data sets from data series where value of [B] is constant/same so that it gets cancelled out. In this case the data sets are 1 and 2. Divide the rate law for these two sets of data and you get rate3/rate1 = ([A]3^m x [B]3^n) / ([A]1^m x [B]1^n) ---> 24.47 / 2.83 = (0.819^m x 0.763^n) / (0.273^m x 0.763^n) ---> 8.65 = 3^m ----> m = 2. similarly in order to find n, that is, order with respect to B use data sets 1 and 2. rate2/rate1 = ([A]2^m x [B]2^n) / ([A]1^m x [B]1^n) ---> 2.83 / 2.83 = (0.273^m x 1.526^n) / (0.273^m x 0.763^n) ---> 1 = 2^n ----> n = 0. Now the complete rate law of mentioned equation can be written as rate=k [A]^2. 4) Use the just determined rate law, that is, rate=k [A]^2 to for set 1 to find the rate constant k as shown below. k = rate / [A]^2 ----> k = 2.83/ (0.273)^2 = 37.97 M^-1 S^-1
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