3)The data in the table below were obtained for the reaction: A + B ----> P Use

Question

3)The data in the table below were obtained for the reaction: A + B ----> P Use this info for quest 3 and 4.

3) Write the rate law for this reaction

4) Calculate the magnitude of the rate constant (with units) please include explanation I appreciate it and will rate well thank you and solved for me so that I may understand for my test please. I get confused on how to get the rate law

Experiment

[A} [M]

[B] [M]

Initial rate

1

0.273

0.763

2.83

2

0.273

1.526

2.83

3

0.819

0.763

24.47

Experiment

[A} [M]

[B] [M]

Initial rate

1

0.273

0.763

2.83

2

0.273

1.526

2.83

3

0.819

0.763

24.47

Explanation / Answer

3) The rate law of reaction mentioned in the problem is rate=k [A]^m x [B]^n, where m and n are order with respect to reactants A and B. In order to find the value of m, that is order with respect to A, search two data sets from data series where value of [B] is constant/same so that it gets cancelled out. In this case the data sets are 1 and 2. Divide the rate law for these two sets of data and you get rate3/rate1 = ([A]3^m x [B]3^n) / ([A]1^m x [B]1^n) ---> 24.47 / 2.83 = (0.819^m x 0.763^n) / (0.273^m x 0.763^n) ---> 8.65 = 3^m ----> m = 2. similarly in order to find n, that is, order with respect to B use data sets 1 and 2. rate2/rate1 = ([A]2^m x [B]2^n) / ([A]1^m x [B]1^n) ---> 2.83 / 2.83 = (0.273^m x 1.526^n) / (0.273^m x 0.763^n) ---> 1 = 2^n ----> n = 0. Now the complete rate law of mentioned equation can be written as rate=k [A]^2. 4) Use the just determined rate law, that is, rate=k [A]^2 to for set 1 to find the rate constant k as shown below. k = rate / [A]^2 ----> k = 2.83/ (0.273)^2 = 37.97 M^-1 S^-1

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.