A technician at Nature\'s Best Vinegar titrated a vinegar sample from another ba

Question

A technician at Nature's Best Vinegar titrated a vinegar sample from another batch. Here are the data he collected: concentration of sodium hydroxide, M 0.5000 final buret reading, mL 32.46 initial buret reading, mL 23.81 volume of vinegar sample titrated, mL 10.00 What was the molarity of acetic acid in the vinegar sample? What was the mass percent of acetic acid in the vinegar sample?

Explanation / Answer

(a) 10 x M = 0.5 x (32.46 - 23.81) => M = 0.4325 Molar acetic acid (b) Molar mass of acetic acid = 60, Therefore mass of acetic acid in soln = 60 x 0.4325 x 10 / 1000 = 0.2595 g % mass = 0.2595 x 100 / 10 = 2.595 %

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